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Question

The set of zeros of the cubic polynomial f(x)=x3āˆ’2x2+x is

A
{0,1,3}
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B
{0,1,2}
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C
{0,1}
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Solution

The correct option is C {0,1}
Given: f(x)=x32x2+x

We see that x is common in all the terms of the polynomial, hence we can write f(x) as
f(x)=x(x22x+1)
f(x)=x(x1)2
Hence theset of zeros of f(x) are {0,1,1} or {0,1}

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