The set of zeros of the cubic polynomial f(x)=x3ā2x2+x is
A
{0,1,3}
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B
{0,1,2}
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C
{0,1}
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Solution
The correct option is C{0,1} Given: f(x)=x3−2x2+x
We see that x is common in all the terms of the polynomial, hence we can write f(x) as f(x)=x(x2−2x+1) ⇒f(x)=x(x−1)2
Hence theset of zeros of f(x) are {0,1,1}or {0,1}