The set S and E are defined as given below- S- x- y - - x-3 - 1 and - y-3 - 1 E- x- y -4x2-9y2-32x-54y-109- 0 then S- E If true enter 0 else enter 1-

In E,4x^2+9y^2 32x 54y+109≤ 0 (x 4)^29+(y 3)^24≤ 1 (x,y) are points on or inside the ellipse x 3∈ [ 2,4],|y 3|∈ [0,2] S ⊂ E The correct ...

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The set S and E are defined as given below: $S = {(x, y) : | x - 3 | < 1 a n d | y - 3 | < 1}$ $E = {(x, y) : 4 x^{2} + 9 y^{2} - 32 x - 54 y + 109 \leq 0}$ then $S \subset E$
If true enter 0 else enter 1.

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S

E

S = {(x, y) : | x - 3 | < 1

| y - 3 | < 1}

E = {(x, y) : 4 x^{2} + 9 y^{2} - 32 x - 54 y + 109 \leq 0}

S \subset E

A

B

A = {(x, y) : | x - 3 | < 1

| y - 3 | < 1}

B = {(x, y) : 4 x^{2} + 9 y^{2} - 32 x - 54 y + 109 \leq 0}

\frac{d y}{d x} + \frac{y}{x} = y^{2} .

k x = e^{1 / x y}

\frac{d y}{d x} + \frac{y^{2}}{x} = y

k x = e^{1 / v} = e^{x / y}

sin x = cos y

x + y = 45^{0}

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