Question

The settlement of prototype in clayey material may be estimated using plate load test data from the following expression:

• A. $S_{\text{prototype}}=S_{\text{plate}}\times \left(\frac{B_{\text{prototype}}}{B_{\text{plate}}}\right)$
• B. $S_{\text{prototype}}=S_{\text{plate}}\times \left(\frac{B_{\text{plate}}}{B_{\text{prototype}}}\right)$
• C. $S_{\text{prototype}}=S_{\text{plate}}\times {\left[\frac{2B_{\text{prototype}}}{B_{\text{prototype}}+B_{\text{plate}}}\right]}^2$
• D. $S_{\text{prototype}}=S_{\text{plate}}\times {\left[\frac{B_{prototype}+B_{plate}}{2B_{\text{prototype}}}\right]}^2$

Answer 1

The correct option is A $S_{\text{prototype}}=S_{\text{plate}}\times \left(\frac{B_{\text{prototype}}}{B_{\text{plate}}}\right)$

For clayey soil,

$\frac{\text{Settlement of footing}}{\text{Settlement of plate}}=\frac{\text{Width of footing}}{\text{Width of plate}}$

$\frac{S_f}{S_P}=\frac{B_f}{B_P}$

$\frac{S_{\text{prototype}}}{S_{\text{plate}}}=\frac{B_{\text{prototype}}}{B_{\text{plate}}}$

$S_{\text{prototype}}=S_{\text{plate}}\times \left(\frac{B_{\text{prototype}}}{B_{\text{plate}}}\right)$

Note: For sandy soil,

$\frac{S_f}{S_P}={\left[\frac{B_f}{B_P}\left(\frac{B_P+0.3}{B_f+0.3}\right)\right]}^2$