wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The setup in the figure is used to measure resistance R. The ammeter and voltmeter resistance are 0.01Ω and 2000Ω respectively. Their readings are 2 A and 180 V respectively, giving a measured resistance of 90Ω. The percentage error in the measurement is _______.


  1. -4.5

Open in App
Solution

The correct option is A -4.5
Measured value of resistance = 90Ω

Resistance of voltmeter, Rv=2000Ω

Voltage across voltmeter, V = 180 V

Curent through voltmeter,

=VRV=1802000=0.09A

Curent through resistance, R

IR=2IV=(20.09)A

IR=1.91A

True value of resistance,

VIR=1801.91=94.24Ω

%error=9094.2494.24×100=4.5%

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Concept of Error-1
MEASUREMENT
Watch in App
Join BYJU'S Learning Program
CrossIcon