Question

The shaded part of a given figure indicates the feasible region, then the constraints are

• A. $x,y\ge 0,x+y\ge 0,x\ge 5,y\le 3$
• B. $x,y\ge 0,x-y\ge 0,x\le 5,y\le 3$
• C. $x,y\ge 0,x-y\ge 0,x\le 5,y\ge 3$
• D. $x,y\ge 0,x-y\le 0,x\le 5,y\le 3$

Answer 1

Answer: (B)

$x,y\ge 0,x-y\ge 0,x\le 5,y\le 3$

Now, as the graph is in first quadrant. So, $x\ge 0,y\ge 0$,

The region lies to the left of the line $x=5$, So $x\le 5$

It lies below the line $y=3$, So $y\le 3$

Also, the region lies to the right of the line $x=y$. So, $x\ge y$ or $x-y\ge 0$

answer (b)