The shaded portion in the adjoining figure shows a circular path enclosed by two concentric circles. If the inner circumference of the path is 176 m and the uniform width of the circular path is 3.5 m, find the area of the path.
Let the radius of the inner circle be r.
⇒2πr=176 m⇒2×227×r=176
⇒r=176×72×22=28 m
Since, the width of the path = 3.5 m,
radius of the outer circle (R) = r + 3.5 m = 28 m + 3.5 m = 31.5 m
The area of the circular path
= Area of the outer circle – Area of the inner circle
=πR2–πr2
=(227×31.5×31.5) – (227×28×28)=3118.5 – 2464=654.5 m2