The shaded portion in the figure given below shows a circular path enclosed by two concentric circles. If the inner circumference of the path is 176 m and the uniform width of the circular path is 3.5 m. Find the area of the path.
654.5 m2
Let the radius of the inner circle be r m
Therefore, 2πr=176⇒2×227×r=176m
⇒r=176×72×22m=28m
Since, the width of the path = 3.5 m
The radius of the outer circle(R) = r + 3.5 m = 28 m +3.5 m = 31.5 m
The area of the circular path = Area of the outer circle – Area of the inner circle
= πR2–πr2
= (227×31.5×31.5)–(227×28×28)
= 3118.5 – 2464 = 654.5 m2