The shaded region in the figure is the solution set of the inequations

[1 mark]

6 x + 4 y \geq 24, x \leq 4, y \leq 5, x, y \geq 0

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6 x + 4 y \leq 24, x \geq 4, y \leq 5, x, y \geq 0

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6 x + 4 y \leq 24, x \geq 4, y \geq 5, x, y \geq 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 x + 4 y \geq 24, x \geq 4, y \leq 5, x, y \geq 0

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Solution

The correct option is A $6 x + 4 y \geq 24, x \leq 4, y \leq 5, x, y \geq 0$
The line joining $(4, 0)$ and $(6, 0)$ is $6 x + 4 y = 24$
The shaded region is bounded by $6 x + 4 y \geq 24, x \leq 4, y \leq 5, x, y \geq 0$
Therefore, option (a) is correct.

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