The shaded region in the figure is the solution set of the inequations.

4 x + 5 y \leq 20, 3 x + 10 y \leq 30, x \leq 6, x, y \geq 0

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4 x + 5 y \geq 20, 3 x + 10 y \leq 30, x \leq 6, x, y \geq 0

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4 x + 5 y \leq 20, 3 x + 10 y \leq 30, x \geq 6, x, y \geq 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 x + 5 y \geq 20, 3 x + 10 y \leq 30, x \geq 6, x, y \geq 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is B $4 x + 5 y \geq 20, 3 x + 10 y \leq 30, x \leq 6, x, y \geq 0$
From the graph
the equations are
$4 x + 5 y = 20, . . . . . (1) 3 x + 10 y = 30, . . . . . (2) x = 6, . . . . (3) x, y \geq 0$
so the area is above (1),below (2)and(3), and above x and y axis so the solution set of equation is $4 x + 5 y \geq 20, 3 x + 10 y \leq 30, x \leq 6, x, y \geq 0$

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