Question

The shape of $(C{H}_3{)}_{3}N$ is pyramidal because:

• A. nitrogen forms three $s{p}^3$ hybridised $\sigma$ bonds with carbon atoms of methyl groups and there is one non-bonding electron pair
• B. nitrogen forms three $s{p}^2$ hybridised $\sigma$ bonds with carbon atoms of methyl groups and fourth orbital forms $\pi$ bond
• C. nitrogen has five valencies which are arranged in pyramidal shape
• D. the unpaired electron present on nitrogen is delocalised

Answer 1

The correct option is A nitrogen forms three $s{p}^3$ hybridised $\sigma$ bonds with carbon atoms of methyl groups and there is one non-bonding electron pair

The shape of $(C{H}_3{)}_{3}N$ is pyramidal or distorted tetrahedral, as the central nitrogen forms three $\sigma$ bonds with carbon of methyl groups and has one lone pair of electrons, like ammonia and shows $s{p}^3$ hybridisation. Due to the presence of a lone pair of electrons, it forms pyramidal shape instead of tetrahedral as is usually seen for $s{p}^3$ hybridised molecules.