The shape of $[C H_{3}]^{+}$ is Triangular planar. If true enter 1, else enter 0.

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Solution

The shape of $[C H_{3}]^{+}$ is triangular planar.
$C H_{3}^{+}, s p^{2}$ carbon
In carbocations, carbon atom is $s p^{2}$ -hybridized and they have a triangular planar shape.

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