Question

The shape of $I{F}_7$ is

• A. Tetrahedral
• B. Trigonal bipyramidal
• C. Octahedral
• D. Pentagonal bipyramidal

Answer 1

The correct option is D Pentagonal bipyramidal

Let's apply VSEPR and hybridisation theory here.

Iodine has 7 valence electrons and there are 7 fluorine atoms.

So, electron pairs (e.p) = $\frac{7+7}{2}=7$

From this, we can say the hybridisation will be $s{p}_3{d}_3$

So, the structure will be pentagonal bipyramidal.