The shape of $S F_{4}$ and $X e F_{2}$ respectively are:

trigonal bipyramidal and trigonal bipyramidal

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see-saw and linear

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T-shape and linear

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square planar and trigonal bipyramidal

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Solution

The correct option is B see-saw and linear
$S F_{4}$ has a see-saw shape as it contains four bond pairs and one lone pair.

$X e F_{2}$ has ${s p}_{3} d$ hybridisation and linear geometry due to the presence of three lone pairs.

Hence option B is correct.

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