The shape of solid iron rod is cylindrical. Its height is 11 $c m$ . and base diameter is 7 cm. Then find the total volume of 50 such rods.

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Solution

Height of cylinder is $11 c m$
Diameter of cylinder $7 c m$
Volume of cylinder $π r^{2} h \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times 11 \frac{121}{2} \times 7 = 423.5$
Volume of $50$ such rods $50 \times 423.5 = 21175 c m^{2}$

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The shape of solid iron rod is cylindrical. Its height is 11cm . and base diameter is 7 cm. Then find the total volume of 50 such rods.

Height of cylinder is 11cmDiameter of cylinder 7cmVolume of cylinder πr2h227×72×72×111212×7=423.5Volume of 50 such rods 50×423.5=21175cm2

The shape of solid iron rod is cylindrical. Its height is 11 $c m$ . and base diameter is 7 cm. Then find the total volume of 50 such rods.

Height of cylinder is $11 c m$
Diameter of cylinder $7 c m$
Volume of cylinder $π r^{2} h \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times 11 \frac{121}{2} \times 7 = 423.5$
Volume of $50$ such rods $50 \times 423.5 = 21175 c m^{2}$