Question

The shape of the top of a table in a restaurant is that of a segment of a circle with the centre $O$ and $\angle BOD={90}^{\circ },BO=OD=60$ cm. Find the perimeter of the table

Answer 1

Perimeter of the table $=\frac{3}{4}\times 2\pi r+2r$

$=\frac{3}{4}\times 2\times \frac{22}{7}\times 60+2\times 60$

$=\frac{3\times 2\times 22\times 60}{4\times 7}+120$

$=\frac{3\times 11\times 60}{7}+120$

$=282.85+120$

$=402.85$cm