The shape of $X e F_{5}^{-}$ will be:

square pyramidal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

trigonal bipyramidal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

planar

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

pentagonal bipyramidal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B planar
No. of electron pair $= \frac{8 + 5 + 1}{2} = 7$ . Number of bond pair $= 5$ . Number of lone pair $= 2$ .
As lone pairs are present axially to minimize the repulsion, hence, the shape is planar.

Suggest Corrections

Similar questions

[X e F_{5}]^{-}

X e O_{3} F_{2},

P C l_{5}

I F_{5}

X e F_{5}^{+} ?

I C l_{2}^{-}

What will be the geometry and shape of $N H_{2}^{-}$ ?

Join BYJU'S Learning Program