CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Shape and Geometry Using VSEPR

The shape of ...

Question

The shape of $X e O_{2} F_{2}$ is :

A

Trigonal Planar.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

See-saw.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

Square Planar.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

Tetrahedral.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B See-saw.

The molecules assume different geometries based on the number of bond pairs/lone pairs in the valence shell of the central atom. The pi electrons are not involved in deciding the geometry of the molecule.
$X e O_{2} F_{2}$ has the general formula $A B_{4} L$
It has 4 bonding pairs, and one lone pair. The electronic geometry is of type Trigonal Bipyramidal and the shape is See-Saw.

Suggest Corrections

thumbs-up

3

Similar questions

Q. The shape of

X e O_{2} F_{2}

Q. The shape of

X e O_{2} F_{2}

Q. The shapes of

P C l_{4}^{+}, P C l_{4}^{-}

A s C l_{5}

are respectively:

Q. The shape and geometry of

X e F_{4}

are respectively:

Q. The shape of

X e F_{2}, X e F_{4}

X e O_{2} F_{2}

are respectively.

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Shape and Geometry Using VSEPR

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon