The shapes of $I F_{5}$ and $I F_{7}$ are respectively:

tetragonal pyramidal and pentagonal bipyramidal

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octahedral and pyramidal

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trigonal bipyramidal and square antiprismatic

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distorted square planar and distorted octahedral

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Solution

The correct option is A tetragonal pyramidal and pentagonal bipyramidal
$I$ has $7$ valence electrons making $7 I - F$ bond pairs in ${I F}_{7}$ which makes it pentagonal bipyramidal
In ${I F}_{5}$ it has $5$ bond pairs and $1$ lone pair making it tetragonal pyramidal

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