Question

The shear lag width for ISA ($75\times 75\times 10)$ is (Assume gauge distance = 40 mm)

• A. $100\text{mm}$
• B. $105\text{mm}$
• C. $150\text{mm}$
• D. 120 mm

Answer 1

The correct option is B $105\text{mm}$


The length of outstanding leg will be, w = 75 mm and gauge distance, $w_1=40\text{mm}$.
So, the shear lag width, $b_s=w+w_1-t$
$=75+40-10$
= 105 mm