Question

The shearing strain produced in a block of metal subjected to a shearing stress of ${10}^{8}N/m^2$ is
(Modulus of rigidity $\eta =8\times {10}^{10}N/m^2)$

• A. $1.1\times {10}^{-3}$
• B. $1.5\times {10}^{-3}$
• C. $1.25\times {10}^{-3}$
• D. $1.6\times {10}^{-3}$

Answer 1

The correct option is C $1.25\times {10}^{-3}$

The modulus of rigidity is defined as $\eta =\frac{shearingstress}{shearingstrain}$

Thus, $shearingstrain=\frac{shearingstress}{\eta }=\frac{{10}^8}{8\times {10}^{10}}=0.125\times {10}^{-2}=1.25\times {10}^{-3}$