Question

The short and long hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distance travelled by their tips in 2 days.

Answer 1

In $2$ days, the short hand will complete 4 rounds.

$\therefore$ Distance moved by its tip = 4(circumference of a circle of radius 4 cm)

$=4\times (2\times \frac{22}{7}\times 4)cm=\frac{704}{7}cm$

In 2 days, the long hand will complete 48 rounds.

$\therefore$ Distance moved by its tip = 48(circumference of a circle of radius 6 cm)

$=48\times (2\times \frac{22}{7}\times 6)cm=\frac{12.672}{7}cm$

Hence,
sum of distances moved by the tips of two hands of the clock

$=(\frac{704}{7}+\frac{12672}{7})cm$ $=$ $1910.85cm$