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Question

The shortest distance between the liney-x=1 and the x=y2 is


A

328

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B

238

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C

325

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D

34

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Solution

The correct option is A

328


Explanation for the correct option.

Find the shortest distance.

Let the point on the curve be α2,α.

Then, the distance will be d=(α-α2-1)2

d=α2-α+12....(1)

Now, applying the concept of maxima and minima to find coordinates of the point.

dddα=d(α2-α+1)dαdddα=2α-1=0α=12

Putting the value of α in (1)

d=14-12+12=328units

Hence, option A is the correct answer.


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