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Question

The shortest distance between the pair of skew lines:
x=y+2=z+2 and x2=y+1=z+1 is 1n. Then the value of n is:

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Solution


Given lines :
L1:x=y+2=z+2 and L2:x2=y+1=z+1
L1:x1=y21=z21,L2:x21=y11=z+11
D.Rs of L1=(a1,b1,c1)=(1,1,1) and D.Rs of L2=(a2,b2,c2)=(1,1,1)
shortest distance =∣ ∣ ∣ ∣ ∣ ∣ ∣∣ ∣x2x1y2y1z2z1a1b1c1a2b2c2∣ ∣(b1c2b2c1)2∣ ∣ ∣ ∣ ∣ ∣ ∣=∣ ∣ ∣ ∣ ∣ ∣ ∣∣ ∣213111111∣ ∣(11)2+(11)2+(1+1)2∣ ∣ ∣ ∣ ∣ ∣ ∣=222=12
So, n=2

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