The shortest distance from the origin to a variable point on the sphere $(x - 2)^{2} + (y - 3)^{2} + (z - 6)^{2} = 1$ is

5

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6

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7

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8

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Solution

The correct option is B $6$
Sphere $(x - 2)^{2} + (y - 3)^{2} + (z - 6)^{2} = 1$
Centre $(2, 3, 6) and radius A C = 1$
Distance betweeb centre and origin $O C = \sqrt{2^{2} + 3^{2} + 6^{2}} = \sqrt{49} = 7$
Shortest distance $= | O C - A C | = | 7 - 1 | = 6$
(Origin lies outside the sphere)

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(x - 2)^{2} + (y - 3)^{2} + (z - 6)^{2} = 1

Mark the correct option:

If , the value of x is

A. 5

B. 6

C. 7

D. 8

A = {x : x

}

A

y = e^{2 x}

x^{2}

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