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Question

The shortest λ for the Lyman series of hydrogen atom is:


[Given, RH=109678cm1]

A
911.7Ao
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B
700Ao
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C
600Ao
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D
811Ao
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Solution

The correct option is A 911.7Ao
For Lyman series, n1=1

For shortest λ of Lyman series; energy difference in two levels showing transition should be maximum i.e n2=

1λ=RH[1121()2]

1λ=109678

λ =911.7×108 cm

=911.7A0

Hence, option A is correct.

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