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Byju's Answer
Standard XII
Physics
Validating the Bohr's Model
The shortest ...
Question
The shortest wavelength for Lyman series is
912
o
A
. Find shortest wavelength for Paschen and Brackett series in Hydrogen atom.
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Solution
Given shortest wavelength
λ
=
912
∘
A
1
λ
=
R
Z
2
(
1
n
′
2
−
1
n
2
)
For shortest wavelength in Paschen series the two levels showing transition should be maximum.
n
=
∞
1
λ
=
1.097
×
10
7
(
1
3
2
−
1
∞
2
)
λ
=
8.20
×
10
−
7
m
=
8200
A
∘
For shortest wavelength in Brackett series the two levels showing transition should be maximum.
n
=
∞
1
λ
=
1.097
×
10
7
(
1
4
2
−
1
∞
2
)
λ
=
14.58
×
10
−
7
m
=
14580
A
∘
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