Question

The shortest wavelength in the Lyman series of hydrogen spectrum is $912A^o$corresponding to a photon energy of 13.6 eV. The shortest wavelength in the Balmer series is:

• A. $3648A^o$
• B. $228A^o$
• C. $6566A^o$
• D. $8208A^o$

Answer 1

Answer: (A)

$3648A^o$

In Lyman series $({\lambda }_{min}{)}_L=\frac{1}{R}$ and $({\lambda }_{min}{)}_B=\frac{4}{R}$
$\Rightarrow ({\lambda }_{min}{)}_B=4\times ({\lambda }_{min}{)}_L=4\times 912=3648\stackrel{o}{A}$