Question

The $Si$ diode and the $Ge$ diode start conducting at $0.7\text{V}$ and $0.3\text{V}$ respectively, in the given circuit. If the $Ge$ diode connection be reversed. What will be the values of $V_0$ ​ and $I?$

• A. $2.34\text{mA},12.7\text{V}$
• B. $2.26\text{mA},11.3\text{V}$
• C. $2.26\text{mA},11.7\text{V}$
• D. $2.34\text{mA},11.7\text{V}$

Answer 1

The correct option is B $2.26\text{mA},11.3\text{V}$

When the connections of Ge diode are reversed, then current will through silicon.

$\therefore I=\frac{12-0.7}{5\times {10}^3}=2.26\times {10}^{-3}\text{A}=2.26\text{mA}$

Output voltage, $V_0=V-V_{Si}=12-0.7=11.3\text{V}$

Hence, $\left(C\right)$ is the correct answer.