The SI unit of a physical quantity having the dimensional formula of ${M L}^{0} T^{- 2} A^{- 1}$ is:

t e s l a

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w e b e r

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a m p - m e t e r

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a m p

m^{2}

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Solution

The correct option is B $t e s l a$
$a m p$ $m^{2} = A^{1} L^{2}$
$a m p$ $m e t e r$ $= A^{1} L^{1}$
$w e b e r$ $= M L^{2} A^{- 1} T^{- 2}$
$A \to$ ampere
$T e s l a$ $= M^{1} L^{0} T^{- 2} A^{- 1}$
Hence, option A is correct answer.

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