The SI unit of the inductance, the henry can be written as: (given energy = LI22), where L is inductance and I is electric current.
A
Joule
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B
volt-second / ampere
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C
joule/(ampere)2
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D
ohm-second
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Solution
The correct options are B volt-second / ampere Cjoule/(ampere)2 D ohm-second (a) The given formula suggests that unit of current will be there with unit of energy. (b) Energy=Vq and q=IT (c) U=12Li2 ∴L=2Ui2=joule(ampere)2 (d) U=12Li2=i2Rt ∴L=Rt or henry = ohm-second