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Question

The side BC of a ABC produced, such that D is on ray BC. The bisector of A meets BC in L. Prove that ABC + ACD = 2ALC. [3 MARKS]

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Solution

Process : 2 Marks
Proof : 1 Mark


In ΔABC,

ACD = B + A

ACD = B + 21 ..........(i)

In ΔABL,

ALC = B + BAL

ALC = B + 1

2ALC = 2B +21 ......(ii)

Subtracting (i) from (ii), we get

2ALC - ACD = B

ACD + B = 2ALC

ACD + ABC = 2ALC


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