Question

The side of a cubical chalk box is $4cm$. Find the total surface area of the chalk box a length of its diagonal.

Answer 1

Surface area of cubical chalk box $=6a^2$
where a = edge of cubical box
Here $a=4cm$
Surface Area$=6\times (4{)}^2=96c{m}^2$
Diagonal of a cube$=\sqrt{3}a$
Diagonal$=\sqrt{3}\times 4=4\sqrt{3}cm$