Let the rhombus be ABCD, Let the intersecting point of the diagonals be O
Given,
AB=BC=CD=AC=13cm
AC=24cm
Since the diagonals of a rhombus bisect each other at right angles a right triangle BOC is formed.
According to the Pythagoras Theorem,
(BO)^2+(CO)^2=(BC)^2
Since the diagonals bisect each other
CO=CA/2
= 24cm/2=12cm
Therefore (BO)^2+(CO)^2=(BC)^2
(BO)^2=(BC)^2-(CO)^2
(BO)^2=(13cm)^2-(12cm)^2
(BO)^2=(169-144)cm
BO=sqrt(25)cm
=5cm
Therefore its other diagonal is (5cm*2)
= 10cm long