The side of a triangle are given by 3x2 - y2; 4x2 -7xy+ 4y2 and -3x2+ 7xy + 8y2. Find its perimeter -.-"

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Solution

Answer :

Given sides of triangle = 3x² - y² , 4x² - 7xy + 4y² and - 3x² + 7xy + 8y ²

We know Perimeter of triangle = Sum of length of all sides .

So,

Perimeter of given triangle = 3x² - y² + 4x² - 7xy + 4y² + ( - 3x² + 7xy + 8y ² )

Perimeter of given triangle = 3x² - y² + 4x² - 7xy + 4y² - 3x² + 7xy + 8y ²

Perimeter of given triangle = 4x² + 11y² ( Ans )

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