The side of a triangle are in the ratio 1-2 - 1-3 - 1-4 and its perimeter is 104 cm- The length of the longest side is

The correct option is C 48 cmThe perimeter of triangle = sum of sides of the triangle ⇒x2+x3+x4=104 ⇒13x12=104 ⇒ x=104× 1213=96 Longest side ...

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Standard VI

Mathematics

Word Problems

The side of a...

Question

The side of a triangle are in the ratio $\frac{1}{2} : \frac{1}{3} : \frac{1}{4}$ and its perimeter is 104 cm. The length of the longest side is

52 cm

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48 cm

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32 cm

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26 cm

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Solution

The correct option is C 48 cm
The perimeter of triangle = sum of sides of the triangle

$\Rightarrow \frac{x}{2} + \frac{x}{3} + \frac{x}{4} = 104$

$\Rightarrow \frac{13 x}{12} = 104$
$\Rightarrow x = \frac{104 \times 12}{13} = 96$
Longest side $= \frac{x}{2} = \frac{96}{2} = 48 c m$

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The side of a triangle are in the ratio 12:13:14 and its perimeter is 104 cm. The length of the longest side is

The correct option is C 48 cmThe perimeter of triangle = sum of sides of the triangle⇒x2+x3+x4=104⇒13x12=104⇒x=104×1213=96Longest side =x2=962=48cm

The side of a triangle are in the ratio $\frac{1}{2} : \frac{1}{3} : \frac{1}{4}$ and its perimeter is 104 cm. The length of the longest side is

The correct option is C 48 cm
The perimeter of triangle = sum of sides of the triangle

$\Rightarrow \frac{x}{2} + \frac{x}{3} + \frac{x}{4} = 104$

$\Rightarrow \frac{13 x}{12} = 104$
$\Rightarrow x = \frac{104 \times 12}{13} = 96$
Longest side $= \frac{x}{2} = \frac{96}{2} = 48 c m$