Question

The Side of $△$ ABC are $AB=\sqrt{13}cm,BC=4\sqrt{3}cm,CA=7cm$, Then $sin\theta$,
Where $\theta$ is the smallest angle of the triangle, is equal to

• A.
• B.
• C.
• D. None of these

Answer 1

The correct option is B

$cos\theta =\frac{49+48-13}{2.28\sqrt{3}}=\frac{\sqrt{3}}{2}\Rightarrow \theta ={30}^o\Rightarrow sin\theta =\frac{1}{2}$