The sides BA and DC of the parallelogram ABCD are produced as shown in figure. Then
A
∠a=∠x+∠y
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B
∠a=∠b=12(∠x+∠y)
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C
∠y=∠a−∠b
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D
∠a+∠b=∠x+∠y
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Solution
The correct option is D∠a+∠b=∠x+∠y In the given figure, AB || DC ∴∠a=∠x⋯(1) [Alternate Interior Angles] And ∠b=∠y⋯(2) [Alternate Interior Angles] Adding (1) and (2), we get ∠a+∠b=∠x+∠y