The sides BC, CA and AB of ΔABC are produced in order to form exterior angles ∠ACD, ∠BAF and ∠CBE respectively, then ∠BAF+∠ACD+∠CBE is
By angle sum property, x+y+z=180∘ ∠BAF+∠ACD+∠CBE =(180∘−x)+(180∘−y)+(180∘−z) =540∘−(x+y+z)=540∘−180∘=360∘
Sides BC, CA and AB of a triangle ABC are produced in an order, forming exterior angles ∠ACD, ∠BAE and ∠CBF. Show that ∠ACD + ∠BAE + ∠CBF = 360°.