The sides of a right triangle are 2x+1 2x x-1cm .find x

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Solution

We know that out of these thrre sides
2x+1 is bigger
So it must be hypotenuse
So in right triangle
By pythagoras thorem
by pythagorus (2x+1)^2 =(2 x)^2 +(x-1)^2
4x^2+4x+1 = 4x^2 +x^2-2x+1
4x^2 +4x +1 =5 x^2-4x +1
4x+1 = x^2-2x+1
x^2 - 6x =0
x*(x-6) =0
x = 6

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The sides of a right triangle are 2x+1 2x x-1cm .find x

We know that out of these thrre sides 2x+1 is bigger So it must be hypotenuse So in right triangle By pythagoras thorem by pythagorus (2x+1)^2 =(2 x)^2 +(x-1)^2 4x^2+4x+1 = 4x^2 +x^2-2x+1 4x^2 +4x +1 =5 x^2-4x +1 4x+1 = x^2-2x+1 x^2 - 6x =0 x*(x-6) =0 x = 6

We know that out of these thrre sides
2x+1 is bigger
So it must be hypotenuse
So in right triangle
By pythagoras thorem
by pythagorus (2x+1)^2 =(2 x)^2 +(x-1)^2
4x^2+4x+1 = 4x^2 +x^2-2x+1
4x^2 +4x +1 =5 x^2-4x +1
4x+1 = x^2-2x+1
x^2 - 6x =0
x*(x-6) =0
x = 6