Question

The sides of a right triangle whose hypotenuse is$17\mathrm{cm}$ are _________ and _________.

• A. $8\mathrm{cm}$
• B. $15\mathrm{cm}$

Answer 1

Finding the sides of right triangle.

We know that for every natural number $\mathrm{m}>1\left(2\mathrm{m},{\mathrm{m}}^2–1\mathrm{and}{\mathrm{m}}^2+1\right)$ form a Pythagoream triplet.

Let us consider $m^2+1=17$

So, $m^2=17-1$

$\Rightarrow m^2=16$

$\Rightarrow m=\sqrt{16}$

$\Rightarrow m=4$

So, $2m=2\times 4$

$=8$

And, $m^2-1=4^2-1$

$=16-1$

$=15$

The sides of a right triangle whose hypotenuse is $\mathbf{17}\mathbf{}\mathbf{cm}\mathbf{}\mathbf{are}\mathbf{}\mathbf{8}\mathbf{}\mathbf{cm}\mathbf{}\mathbf{and}\mathbf{}\mathbf{15}\mathbf{}\mathbf{cm}\mathbf{.}\mathbf{}$