The sides Of a square are $x = 6$ , $x = 9$ , $y = 3$ and $y = 6$ . Find the equation of a circle drawn on the diagonal of the square as its diameter.

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Solution

$(x - x_{1}) (x - x_{2}) + (y - y_{1}) (y - y_{2}) = 0$
$(x - 6) (x - 9) + (y - 6) (y - 3) = 0$
$x^{2} - 15 x + 5 y + y^{2} - 9 y + 11 = 0$
$x^{+} y^{2} - 15 x - 9 y + 72 = 0$

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The sides Of a square are x=6, x=9, y=3 and y=6. Find the equation of a circle drawn on the diagonal of the square as its diameter.

(x−x1)(x−x2)+(y−y1)(y−y2)=0(x−6)(x−9)+(y−6)(y−3)=0x2−15x+5y+y2−9y+11=0x+y2−15x−9y+72=0

The sides Of a square are $x = 6$ , $x = 9$ , $y = 3$ and $y = 6$ . Find the equation of a circle drawn on the diagonal of the square as its diameter.

$(x - x_{1}) (x - x_{2}) + (y - y_{1}) (y - y_{2}) = 0$
$(x - 6) (x - 9) + (y - 6) (y - 3) = 0$
$x^{2} - 15 x + 5 y + y^{2} - 9 y + 11 = 0$
$x^{+} y^{2} - 15 x - 9 y + 72 = 0$