Question

The sides of a triangle are 11 cm, 15 cm and 16 cm. The altitude to the largest side is

(a) $30\sqrt{7}cm$

(b) $\frac{15\sqrt{7}}{2}cm$

(c) $\frac{15\sqrt{7}}{4}cm$

(d) 30 cm

Answer 1

The area of a triangle having sides a, b, c and s as semi-perimeter is given by,

, where

We need to find the altitude corresponding to the longest side

Therefore the area of a triangle having sides 11 cm, 15 cm and 16 cm is given by

a = 11 m ; b = 15 cm ; c = 16 cm

The area of a triangle having base AC and height p is given by

We have to find the height p corresponding to the longest side of the triangle.Here longest side is 16 cm, that is AC=16 cm

Therefore, the answer is (c).