Question

The sides of a triangle are 11 m, 60 m and 61m. Altitude to the smallest side is

• A. 11 m
• B. 66 m
• C. 50 m
• D. 60 m

Answer 1

The correct option is D

60 m

Sides of a triangle are 11m, 60m and 61m
$\therefore s=\frac{a+b+c}{2}=\frac{11+60+61}{2}=\frac{132}{2}=66$
$\therefore Area=\sqrt{s(s-a)(s-b)(s-c)}$
= $\sqrt{66(66-11)(66-60)(66-61)}$
= $\sqrt{66\times 55\times 6\times 5}$
= $\sqrt{11\times 6\times 11\times 5\times 6\times 5}$
= $11\times 6\times 5=330m^2$
Now length of altitude on the smallest side
= $\frac{Area\times 2}{base}=\frac{330\times 2}{11}=60m$