Question

The sides of a triangle are $16cm,30cm,34cm$.Its area is

• A. $225c{m}^2$
• B. $225\sqrt{3}c{m}^2$
• C. $240c{m}^2$
• D. $450c{m}^3$

Answer 1

Answer: (C)

$240c{m}^2$

Given sides of triangles are $a=16cm,b=30cm,c=34cm$ respectively

Semiperimeter $s=\frac{16+30+34}{2}cm=\frac{80}{2}=40cm$

By heron's, area of the triangle is

$\sqrt{s(s-a)(s-b)(s-c)}c{m}^2=\sqrt{40(40-16)(40-30)(40-34)}c{m}^2=\sqrt{40\times 24\times 10\times 6}c{m}^2=\sqrt{4\times 10\times 4\times 6\times 10\times 6}c{m}^2=4\times 6\times 10c{m}^2=240c{m}^2$

Answer