Question

The sides of a triangle are $3$cm, $4$ cm and $5$ cm. The area (in cm^2) of the triangle formed by joined the mid points of this triangle is:

• A. $6$
• B. $3$
• C. $\frac{3}{2}$
• D. $\frac{3}{4}$

Answer 1

The correct option is C $\frac{3}{2}$

$3^2+4^2=5^2$
$△$ ABC is a right angled triangle
$\therefore AreaABC=\frac{1}{2}\times AB\times BC$
= $\frac{1}{2}\times 3\times 4=6c{m}^2$
Hence, Area of $△DEF=\frac{1}{2}\times \frac{3}{2}\times \frac{4}{2}=\frac{3}{2}c{m}^2$