Question

The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is

• A. $1322c{m}^2$
• B. $1311c{m}^2$
• C. $1344c{m}^2$
• D. $1392c{m}^2$

Answer 1

The correct option is C $1344c{m}^2$

$s=\frac{a+b+c}{2}$
By Heron's formula,Area of the triangle=$\sqrt{s(s-a)(s-b)(s-c)}$
Where a,b,c are sides of the triangle.

$s=\frac{56+60+52}{2}=84$
Area of the triangle$=\sqrt{84(84-56)(84-60)(84-52)}=\sqrt{1806336}=1344c{m}^2$