Question

The sides of a triangle are 8 cm, 10 cm and 6 cm respectively. Area of this triangle is .

• A. 24 $c{m}^2$
• B. 12 $c{m}^2$
• C. 10 $c{m}^2$

Answer 1

The correct option is A 24 $c{m}^2$

The three sides are $\text{10 cm, 6 cm and 8 cm}$.

$6^2+8^2=36+64=100={10}^2$

By converse of Pythagoras theorem, the triangle is a right-angled triangle. Let's take the sides $\text{6 cm}$ and $\text{8 cm}$ as the base and the height respectively.
$\text{Area of a triangle}$ $=\frac{1}{2}\times \text{base}\times \text{height}$
$Area=\frac{1}{2}\times 6\times 8$ ${cm}^2$
$=24c{m}^2$