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Question

The sides of a triangle are a2−3ab+8, 4a2+5ab−3 and 6−3a2+4ab. Then its perimeter is


A

a2+2ab+11

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B

2a2+6ab+11

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C

2a2+ab+11

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D

2a2+2ab

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Solution

The correct option is B

2a2+6ab+11


Sum of the three sides gives the perimeter of the triangle.

i.e. Perimeter = (a23ab+8)+(4a2+5ab3)+(63a2+4ab)

= a2+4a23a23ab+5ab+4ab+83+6

= 2a2+6ab+11


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