The sides of a triangle are a2−3ab+8, 4a2+5ab−3 and 6−3a2+4ab. Then its perimeter is
2a2+6ab+11
Sum of the three sides gives the perimeter of the triangle.
i.e. Perimeter = (a2−3ab+8)+(4a2+5ab−3)+(6−3a2+4ab)
= a2+4a2−3a2−3ab+5ab+4ab+8−3+6
= 2a2+6ab+11