The correct option is B The triangle is acute-angled
Let ABC is a triangle with sides a,b,c.
if c2<a2+b2 then C is a acute angle.
∴△ABC is a acute angled triangle.
Since, a=4x,b=6x,c=7x
⇒c2=(7x)2=49x2 and
a2+b2=(4x)2+(6x)2=16x2+36x2=52x2
∴c2<a2+b2
⇒Given,△ is a acute angled triangle.
Option B is correct.