The sides of a triangle are in the ratio 1-2- 1-3- 1-4 and its perimeter is 104 cm- The length of the longest side is A- 52 cm-B- 48 cmC- 32 cmD- 26 cm

The correct option is B 48 cmSides are in the ratio 1/2:1/3:1/4 i.e. 6 : 4 : 3 Let the sides be 6x, 4x and 3x Given that 6x + 4x + 3x = 104 ⇒ 13x = 104 ⇒ x=8 ...

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Standard VII

Mathematics

Ratios

The sides of ...

Question

The sides of a triangle are in the ratio $\frac{1}{2} : \frac{1}{3} : \frac{1}{4}$ and its perimeter is 104 cm. The length of the longest side is

48 cm

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32 cm

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26 cm

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52 cm.

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Solution

The correct option is A 48 cm
Sides are in the ratio $\frac{1}{2} : \frac{1}{3} : \frac{1}{4}$
i.e. 6 : 4 : 3
Let the sides be 6x, 4x and 3x
Given that 6x + 4x + 3x = 104
$\Rightarrow 13 x = 104$
$\Rightarrow x = 8$
$∴$ Length of longest side $= 6 x = 6 \times 8 = 48 c m$

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The sides of a triangle are in the ratio 12:13:14 and its perimeter is 104 cm. The length of the longest side is

The correct option is A 48 cmSides are in the ratio 12:13:14 i.e. 6 : 4 : 3 Let the sides be 6x, 4x and 3x Given that 6x + 4x + 3x = 104 ⇒13x=104 ⇒x=8 ∴ Length of longest side =6x=6×8=48 cm

The sides of a triangle are in the ratio $\frac{1}{2} : \frac{1}{3} : \frac{1}{4}$ and its perimeter is 104 cm. The length of the longest side is

The correct option is A 48 cm
Sides are in the ratio $\frac{1}{2} : \frac{1}{3} : \frac{1}{4}$
i.e. 6 : 4 : 3
Let the sides be 6x, 4x and 3x
Given that 6x + 4x + 3x = 104
$\Rightarrow 13 x = 104$
$\Rightarrow x = 8$
$∴$ Length of longest side $= 6 x = 6 \times 8 = 48 c m$